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(G)=G^2+12G+2
We move all terms to the left:
(G)-(G^2+12G+2)=0
We get rid of parentheses
-G^2+G-12G-2=0
We add all the numbers together, and all the variables
-1G^2-11G-2=0
a = -1; b = -11; c = -2;
Δ = b2-4ac
Δ = -112-4·(-1)·(-2)
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{113}}{2*-1}=\frac{11-\sqrt{113}}{-2} $$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{113}}{2*-1}=\frac{11+\sqrt{113}}{-2} $
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